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The coordinates of a point on the line $x = 4 y + 5$ , $z = 3 y - 6$ at a distance $3 \sqrt{26}$ from the point $(5, 0, - 6)$ are

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(17,3,3)

(- 7, 3, - 15)

(-17,-3,-3)

(7, - 3, 15)

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detailed solution

Correct option is A

Line is x−54/26=y1/26=z+63/26. A point on this line at a distance 326 from (5, 0, - 6) is ±lr,±mr,±nr= (5 +(3 x 4), 3, - 6+ 9) = (17, 3, 3) or (- 7, - 3, - 15).

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The coordinates of a point on the line x=4y+5, z=3y-6 at a distance 326 from the point (5,0,−6) are

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Ready to Test Your Skills?

free study material

The coordinates of a point on the line $x = 4 y + 5$ , $z = 3 y - 6$ at a distance $3 \sqrt{26}$ from the point $(5, 0, - 6)$ are