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Correct option is A
Any point on the ellipse is given by (8cosθ,18sinθ) Now 2x8+218ydydx=0⇒dydx=−9x4y⇒dydx(8cosθ,18sinθ)=−98cosθ418sinθ= −92cotθ Hence the equation of the tangent at (8cosθ,18sinθ) is y −18 sinθ = 92 cotθ (x−8 cosθ)Therefore, the tangent cuts the coordinate axes at the points0, 18sinθ and 8cosθ, 0Thus the area of the triangle formed by this tangent and the coordinate axes is A=1218⋅8⋅1cosθsinθ=6cosθsinθ=12cosec2θ But cosec 2θ is smallest when θ=π/4. Therefore A is smallest when θ=π/4Hence the required point is 8⋅12⋅18⋅12=(2,3)Talk to our academic expert!
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