The coordinates of the point where the line through 3,-4,-5 and 2,-3,1 crosses the plane 2x+y+z=7 is

Equation of line through (3,-4,-5) and (2,-3,1) is x−3−1=y+41=z+56=tpoint (3-t,-4+t,-5+6t) subtute in given plane now solve this line and the given plane