First slide

Introduction to 3-D Geometry

Question

The coordinates of a point which is equidistance from the points (0, 0, 0), (a,0, 0), (0, b, 0) and (0, 0, c) are given by

Moderate

A

$(\frac{a}{2}, \frac{b}{2}, \frac{c}{2})$
B

$(\frac{a}{3}, \frac{b}{3}, \frac{c}{3})$
C

$(\frac{a}{4}, \frac{b}{4}, \frac{c}{4})$
D

$(- \frac{a}{2}, - \frac{b}{2}, - \frac{c}{2})$

Solution

Let point be (x,y,z). Then
$\begin{array}{l} x^{2} + y^{2} + z^{2} = (x - a)^{2} + y^{2} + z^{2} \\ = x^{2} + (y - b)^{2} + z^{2} \\ = x^{2} + y^{2} + (z - c)^{2} \end{array}$
Therefore $x = \frac{a}{2}, y = \frac{b}{2} and z = \frac{c}{2}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App