First slide

Introduction to 3-D Geometry

Question

The coordinates of a point which is equidistant from the four points $O, A, B$ and $C$ . When $O$ is the origin and $A, B, C$ are the points on the axes of respectively at distances 2,6,4 from the origin in the positive side is

Easy

A

$(1, 2, 3)$
B

$(1, 3, 2)$
C

$(2, 3, 1)$
D

$(- 1, - 3, - 2)$

Solution

Suppose that $P (x_{1}, y_{1}, z_{1})$ be the required point.
It is at equal distances from all four points, $O P = P A = P B = P C$
It gives $x = 1, y = 3, z = 2$
Therefore, the required point is $(1, 3, 2)$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App