The coordinates of two points P and Q are (x1,y1) and (x2,y2) and O is the origin. If circles be described on OP and OQ as diameters then length of their common chord is
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a
|x1y2+x2y1|PQ
b
|x1y2−x2y1|PQ
c
|x1x2+y1y2|PQ
d
|x1x2+y1y2|2PQ
answer is B.
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Detailed Solution
OR=2area of ΔOPQPQ =2×|12(x1y2−x2y1)|PQ =|x1y2−x2y1|PQ