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Questions  

2cos2⁡x+4cos⁡x=3sin2⁡x if 

a
cos⁡x=−2+145
b
cos⁡x=−2+195
c
sin⁡x=−2+145
d
sin⁡x=−2+195

detailed solution

Correct option is B

2cos2⁡x+4cos⁡x=31−cos2⁡x⇒5cos2⁡x+4cos⁡x−3=0⇒cos⁡x=−4±16+6010=−2±195But cos⁡x≠−2−195

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