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Questions  

cos3θcos3θ+sin3θsin3θ is equal to

a
3cos⁡2θcosec⁡2θ
b
3cot⁡2θcosec⁡2θ
c
12cot⁡2θcosec⁡2θ
d
12tan⁡2θsec⁡2θ

detailed solution

Correct option is C

cos⁡3θcos3⁡θ+sin⁡3θsin3⁡θ=4cos3⁡θ−3cos⁡θcos3⁡θ+3sin⁡θ−4sin3⁡θsin3⁡θ=4×3cos2⁡θ−sin2⁡θ4sin2⁡θcos2⁡θ=12cos⁡2θsin⁡2θ×1sin⁡2θ

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