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cos(6600)cot(10500)cosec(−4200)sin(2250)sec(3150)sin(5100)=

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a

2

b

-2

c

12

d

−12

answer is B.

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Detailed Solution

cos(6600)cot(10500)cosec(−4200)sin(2250)sec(3150)sin(5100)=−cos(720−600).cot(1080−300)cosec(360+60 )sin(180+450)sec(360−450)sin(540−300)=−12×-3×23−12×2×12=−2.

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cos(6600)cot(10500)cosec(−4200)sin(2250)sec(3150)sin(5100)=