Q.

cos280+sin280=k3 then cos170=

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a

k32

b

−k32

c

2k3

d

−2k3

answer is A.

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Detailed Solution

We have cos28∘+sin28∘=k3⇒cos28°+cos62°=k3⇒2cos45°cos17°=k3    ∵cosC+cosD=2cosC+D2cosC-D2⇒cos17°=k32
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cos280+sin280=k3 then cos170=