First slide
Properties of ITF
Question

costan1sincot1x=

Moderate
Solution

Let cot1x=θcotθ=x

sincot1x=sinθ=1cosecθ=11+cot2θ=11+x2

Thus, costan1sincot1x

=costan111+x2=cosφ

 Put tan111+x2=ϕtanϕ=11+x2

=1secϕ=11+tan2ϕ=11+11+x2=1+x22+x2

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