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Questions  

cos2u+cos2(u+x)2cosucosxcos(u+x)=1/2 if

a
x=π/4
b
u=π/4
c
x=π/2
d
u=π/2

detailed solution

Correct option is A

L.H.S =cos2⁡u+cos2⁡(u+x)−[cos⁡(u+x)+cos⁡(u−x)]cos⁡(u+x)=cos2⁡u−cos⁡(u−x)cos⁡(u+x)=cos2⁡u−cos2⁡u−sin2⁡x=sin2⁡xso sin2⁡x=1/2⇒sin⁡x=1/2

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