First slide

Introduction to ITF

Question

$\cos^{- 1} \sqrt{\frac{a - x}{a - b}} = \sin^{- 1} \sqrt{\frac{x - b}{a - b}}$ is possible if

Moderate

A

a > x > b or a < x < b
B

a = x = b
C

a > b and x takes any value
D

a < b and x takes any value

Solution

LHS and RHS of the given equation are defined if $\frac{x - b}{a - b} > 0$ and $\frac{x - b}{a - b} > 0$
∴ either a > x > b or a < x < b

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