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cos2x−2cosx=4sinx−sin2xIf:

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a

tanx2=−12

b

tanx=-12

c

tanx2=2+5

d

tanx2=2−5

answer is C.

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Detailed Solution

cos2x−2cosx=4sinx−2sinxcosx⇒cosx−2cosx+2sinx=0⇒cosx+2sinx=0 ∵cosx-2≠0⇒tanx=-12⇒-12=2tanx21−tan2x2⇒tan2x2−4tanx2−1=0⇒tanx2=2±5

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