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Questions  

2cosA=x+1x, 2cosB=y+1y. Then find the value of k if  kcosAB=xy+yx

a
0
b
-1
c
2
d
4

detailed solution

Correct option is C

Given 2cosA=x+1x⇒x2-2xcosA+1=0 ⇒x=2cosA±4cos2A-42=2cosA±i2sinA2=cosA±isinA Similarly 2cosB=y+1y⇒y=cosB±isinB Now xy=cosA±isinAcosB±isinB=e±iAe±iB=e±iA-B Similarly yx=e±iB-A ∴xy+yx=e±iA-B+e±iB-A=cosA-B+cosB-A                                                        =cosA-B+cosA-B                                                        =2cosA-B⇒k=2

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