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Q.

3cosec⁡20∘−sec⁡20∘ is equal to

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a

1

b

2

c

3

d

4

answer is D.

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Detailed Solution

3cosec⁡20∘−sec⁡20∘=3sin⁡20∘−1cos⁡20∘=3cos⁡20∘−sin⁡20∘sin⁡20∘⋅cos⁡20∘=432cos⁡20∘−12sin⁡20∘2sin⁡20∘⋅cos⁡20∘=4sin⁡60∘cos⁡20∘−cos⁡60∘sin⁡20∘sin⁡40∘=4sin⁡40∘sin⁡40∘=4
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3cosec⁡20∘−sec⁡20∘ is equal to