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Questions  

cot1(cosα)tan1(cosα)=x, then sin x =

a
tan2⁡α2
b
cot2⁡α2
c
tan⁡α
d
cot⁡α2

detailed solution

Correct option is A

cot−1⁡(cos⁡α)−tan−1⁡(cos⁡α)=x⇒tan−1⁡1cos⁡α−tan−1⁡(cos⁡α)=x⇒tan−1⁡1cos⁡α−cos⁡α1+1cos⁡αcos⁡α=x ⇒tan−1⁡1−cos⁡α2cos⁡α=x⇒tan⁡x=1−cos⁡α2cos⁡α or cot⁡x=2cos⁡α1−cos⁡α or cosec⁡x=1+cos⁡α1−cos⁡α∴sin⁡x=1−cos⁡α1+cos⁡α=1−1−2sin2⁡α/21+2cos2⁡α/2−1 or sin⁡x=tan2⁡α/2

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