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Questions  

cot712o=

a
1+2+3+4
b
6+3+4+2
c
1+2+4+6
d
3−2+6+4

detailed solution

Correct option is B

cotθ=1+cos2θsin2θ=1+cos15osin15o    where θ=712∘                             =1+3+1223-122=22+3+13-1=22+3+13+13-13+1=26+22+3+3+3+12=2+3+4+6

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