The cubic equation whose roots are thrice to each of the roots of x3+2x2−4x+1=0 is

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x3−6x2+36x+27=0

x3+6x2+36x+27=0

x3−6x2−36x+27=0

x3+6x2−36x+27=0

answer is D.

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Detailed Solution

The equation whose roots are 3 times the roots of fx=0 is f(x3)=0 ⇒x3+6x2-36x+27=0

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