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$A curve g (x) = \int x^{27} {(1 + x + x^{2})}^{6} (6 x^{2} + 5 x + 4) d x is passing through (0,0) then$

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g1=377

g1=277

g2=17

g−1=3714

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Correct option is A

g(x)=∫x241+x+x266x5+5x4+4x3dx= ∫x4+x5+x66⋅6x5+5x4+4x3dx Put t=x6+x5+x4⇒∫t6dt=t77+C=x6+x5+x477+C But it passes through (0,0)⇒C=0

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A curve g(x)=∫x271+x+x266x2+5x+4dx is passing through (0,0) then

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$A curve g (x) = \int x^{27} {(1 + x + x^{2})}^{6} (6 x^{2} + 5 x + 4) d x is passing through (0,0) then$