Q.
For the curve x=t2−1,y=t2−t, the tangent is perpendicular to x-axis then
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a
t=0
b
t=12
c
t=1
d
t=13
answer is A.
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Detailed Solution
x=t2−1, y=t2−t Slope of tangent=(dydx)0=2t−12t=1−12t ∴ Tangent is ⊥lar to x− axis⇒ slope of tangent=∞ ⇒ 1−12t=∞ ⇒t=0
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