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Q.

For the curve x=t2−1,y=t2−t, the tangent is perpendicular to x-axis then

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a

t=0

b

t=12

c

t=1

d

t=13

answer is A.

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Detailed Solution

x=t2−1,  y=t2−t Slope of tangent=(dydx)0=2t−12t=1−12t ∴ Tangent is ⊥lar to x− axis⇒ slope of tangent=∞ ⇒ 1−12t=∞  ⇒t=0
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For the curve x=t2−1,y=t2−t, the tangent is perpendicular to x-axis then