The curve x2−2xy+y2+3x−3y=0 cuts the x-axis at (0, 0) at an angle
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a
π2
b
π6
c
π3
d
π4
answer is D.
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Detailed Solution
x2−2xy+y2+3x−3y=0−−−−(1) dydx= −(2x−2y+3)2x+2y−3 m1= slope of (1)=(dydx)(0,0)=−fxfy=(2x−2y+3)−(2x+2y−3)=1 Slope of Tangent for equation (1) at (0,0)=1 Inclination of Tangent=θ=π4