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Q.

The curve y−exy+x=0  has a vertical tangent at the point

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a

(1,1)

b

(0,1)

c

(1,0)

d

(2,0)

answer is C.

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Detailed Solution

dydx=−(1−yexy)1−x.eyx Since the tangent is a vertical line then 1−x.eyx=0⇒x.eyx=1⇒x=1,y=0
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The curve y−exy+x=0  has a vertical tangent at the point