The curve y=(λ+1)x2+2 intersects the curve y=λx+3 in exactly one point, it λ equals
{-2, 2}
{1}
{-2}
{2}
As (λ+1)x2+2=λx+3 has only one solution, so
D = 0
⇒ λ2−4(λ+1)(−1)=0
or λ2+4λ+4=0
or (λ+2)2=0
∴ λ=−2