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Q.

Cycle tyres are supplied in lots of 10 and there is a chance of 1 in 500 tyres to be defective. Using Poisson’s distribution the approximate number of lots containing no defective tyres in a consignment of 10,000 lots is

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a

9980

b

9998

c

9802

d

9982

answer is C.

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Detailed Solution

λ=1500×10=0.02 P(X=0)=e−0.02 =1−0.021!+(0.02)22!........ =0.9802 The number of lots containing no defective tyre in10000 lots  =10,000×0.9802=9802
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