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Q.

ddxx+ax2+a2x4+a4x8+a8=

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a

15x16−16x15a+a16x−a2

b

x16−x15a+a16x−a2

c

x16−a16x−a

d

x16+a16x+a

answer is A.

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Detailed Solution

ddx1x−a⋅x16−a16=x−a16x15−x16−a16x−a2=15x16−16x15a+a16(x−a)2
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