ddx(|x|)=xxx≠0 then find ddx(log|x|)
1
1x
x
none
x>0ddx|x|=ddx(x)=1=|x|xx<0ddx|x|=ddx(−x)=−1=|x|x∴ddx|x|=|x|xx≠0ddx(log|x|)=1|x|ddx|x|=1|x||x|x=1x(x≠0)