First slide
Introduction to limits
Question

ddx(|x|)=xxx0 then find ddx(log|x|)

Moderate
Solution

x>0ddx|x|=ddx(x)=1=|x|xx<0ddx|x|=ddx(x)=1=|x|xddx|x|=|x|xx0ddx(log|x|)=1|x|ddx|x|=1|x||x|x=1x(x0)

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