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Q.

ddxx+1x2+1x4+1x8+1=15xp−16xq+1x−1−2⇒p,q=

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An Intiative by Sri Chaitanya

a

12,11

b

15,14

c

16,14

d

16,15

answer is D.

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Detailed Solution

(x+1)(x2+1)(x4+1)(x8+1)=(x−1)(x2+1)(x4+1)(x8+1)x−1=x16−1x−1ddxx16−1x−1=(x−1)16x15−(x16−1)1(x−1)2=(15x16−16x15+1)(x−1)−2∴p,q=(16,15).

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ddxx+1x2+1x4+1x8+1=15xp−16xq+1x−1−2⇒p,q=