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Q.

d20ydx202cosxcos3x=

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a

220(cos2x−220cos3x)

b

220(cos2x+220cos4x)

c

220(sin2x+220sin4x)

d

220(sin2x−220sin4x)

answer is B.

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Detailed Solution

y=2cos⁡xcos⁡3x=cos⁡4x+cos⁡2xd4ydx4=44cos⁡4x+24cos⁡2xd4nydx4n=44ncos⁡4x+24ncos⁡2xd20ydx20=420cos⁡4x+220cos⁡2x
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