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Q.

dydx+y=2e2x then y is

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a

ce-x+23e2x

b

(1+x)e-x+23e2x+c

c

ce-x+23e2x+c

d

e-x+23e2x+c

answer is A.

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Detailed Solution

It can be also solved by comparing with the linear equation dydx+Py=Q The integrating factor, I.F=e∫1.dx=ex Therefore, y I.F =∫2e2x .I.F +Cy⋅ex=2∫e3x+C=23e3x+C⇒y=2e2x3+ce−x

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