In the decimal system of numeration of six-digit numbers in which the sum of the digits is divisible by 5 is

First place from left cannot be filled with 0. Next four places can be filled with any of the l0 digits. After filling the first five places, the last place can be filled in following ways:Thus, in any case the last place can be filled in two ways. Hence, the required number of numbers is 9×104 ×2.