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The definite integral $\int_{0}^{1} \sqrt{\frac{1 - x}{1 + x}} d x$ is equal to

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π2−1

π2+12

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Correct option is C

I=∫01 1−x1+xdx=∫01 1−x1−x2dx=sin−1⁡x+1−x201=π2−1

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The definite integral ∫01 1−x1+xdx is equal to

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The definite integral $\int_{0}^{1} \sqrt{\frac{1 - x}{1 + x}} d x$ is equal to