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The definite integral

20x3+3x2+3x+3+(x+1)cos(x+1)dx  equals

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detailed solution

Correct option is C

I=∫−20 x3+3x2+3x+3+(x+1)cos⁡(x+1)dx=∫−20 (x+1)3+2+(x+1)cos⁡(x+1)dxPut x + 1 = t therefore,I=∫−11 t3+2+tcos⁡tdt=4∵t3+tcos⁡t is an odd function .


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