Q.

The degree of the differential equation d2ydx22+dydx2=xsin⁡d2ydx2 is

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a

1

b

2

c

3

d

degree is not defined

answer is D.

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Detailed Solution

The differential equation is not a polynomial in differential coefficients. So its degree is not defined.
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The degree of the differential equation d2ydx22+dydx2=xsin⁡d2ydx2 is