Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

The derivative of x2sin⁡x+cos⁡2x is

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

x2cos⁡x+2xsin⁡x−sin⁡2x

b

x2cos⁡x+2xsin⁡x−2sin⁡2x

c

x2cos⁡x+xsin⁡x−2sin⁡2x

d

x2cos⁡x+2xsin⁡x+2sin⁡2x

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Let, y=x2sin⁡x+cos⁡2xdydx=ddxx2sin⁡x+ddx(cos⁡2x)=x2ddx(sin⁡x)+sin⁡xddxx2+(−2sin⁡2x)=x2cos⁡x+2xsin⁡x−2sin⁡2x
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring