The derivative of x2sin⁡x+cos⁡2x is

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x2cos⁡x+2xsin⁡x−sin⁡2x

x2cos⁡x+2xsin⁡x−2sin⁡2x

x2cos⁡x+xsin⁡x−2sin⁡2x

x2cos⁡x+2xsin⁡x+2sin⁡2x

answer is B.

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Detailed Solution

Let, y=x2sin⁡x+cos⁡2xdydx=ddxx2sin⁡x+ddx(cos⁡2x)=x2ddx(sin⁡x)+sin⁡xddxx2+(−2sin⁡2x)=x2cos⁡x+2xsin⁡x−2sin⁡2x

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