The determinant abaα+bbcbα+caα+bbα+c0=0 is equal to zero, if
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
a, b, c are in A.P.
b
a, b, c are in G.P.
c
α is a root of the equation ax2+bx+c=0
d
(x−α) is a factor of ax2+2bx+c
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Given that abaα+bbcbα+caα+bbα+c0=0Operating C3→C3−C1α−C2, we getab0bc0aα+bbα+c−aα2+bα+bα+c=0⇒ aα2+2bα+cab0bc0aα+bbα+c1=0⇒ ac−b2aα2+2bα+c=0So, either ac−b2=0 or aα2+2bα+c=0This means that either a, b, c are in G.P. or (x−α) is a factor of ax2+2bx+c.