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The determinant equals
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a
152−253
b
253−152
c
35
d
-152+73
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Correct option is A
Taking 5 common from C2 and C3, we get Δ=(5)213+32115+26523+6535Applying C1→C1−13C3−3C2, we get Δ=(5)−321052035=5(−3)(5−6) =5(18)−253=152−253Similar Questions
If ,then is equal to
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