Q.

The determinant Δ=11+ii1+ii1i11+i equals

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a

7+4i

b

-7+4i

c

2i-1

d

(2i-1)

answer is C.

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Detailed Solution

Using C1→C1+C2+C3,we can write ∆=2(1+i)Δ1 whereΔ1=11+ii1i1111+i=11+ii0−11−i0−i1=i [using  R2→R2−R1 and R3→R3−R1Thus, Δ=2(i−1)
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The determinant Δ=11+ii1+ii1i11+i equals