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The determinant $Δ = |\begin{array}{ccc} 1 & 1 + i & i \\ 1 + i & i & 1 \\ i & 1 & 1 + i \end{array}|$ equals

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7+4i

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Correct option is C

Using C1→C1+C2+C3,we can write ∆=2(1+i)Δ1 whereΔ1=11+ii1i1111+i=11+ii0−11−i0−i1=i [using R2→R2−R1 and R3→R3−R1Thus, Δ=2(i−1)

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The determinant Δ=11+ii1+ii1i11+i equals

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The determinant $Δ = |\begin{array}{ccc} 1 & 1 + i & i \\ 1 + i & i & 1 \\ i & 1 & 1 + i \end{array}|$ equals