Q.
The determinant Δ=11+ii1+ii1i11+i equals
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a
7+4i
b
-7+4i
c
2i-1
d
(2i-1)
answer is C.
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Detailed Solution
Using C1→C1+C2+C3,we can write ∆=2(1+i)Δ1 whereΔ1=11+ii1i1111+i=11+ii0−11−i0−i1=i [using R2→R2−R1 and R3→R3−R1Thus, Δ=2(i−1)
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