The determinant y2−xyx2abca′b′c′ is equal to

Let Δ=y2−xyx2abca′b′c′then,Δ=1xyxy2−xyx2yaxbcya′xb′c′y  [Applying C1→xC1,C3→yC3] =1xy0−xy0ax+bybbx+cya′x+b′yb′b′x+c′y   [Applying C1→C1+yC2,C3→C3+xC2] =1xyxyax+bybx+cya′x+b′yb′x+c′y   [Expanding alone R1]=ax+bybx+cya′x+b′yb′x+c′y