The diagonals of the parallelogram whose sides are lx $$+$$ my $$+$$ n $$=$$ $$0$$, lx $$+$$ my $$+$$ n′ $$=$$ $$0$$, mx $$+$$ ly $$+$$ n $$=$$ $$0$$, mx $$+$$ ly $$+$$ n′ $$=$$ $$0$$ include an angle

Question

Infinity Learn · Accepted Answer

Since the distance between the parallel lines lx $$+$$ my $$+$$ n $$=$$ $$0$$ and lx $$+$$ my $$+$$ n′ $$=$$ $$0$$ is same as the distance between the parallel lines mx $$+$$ ly $$+$$ n $$=$$ $$0$$ and mx $$+$$ ly $$+$$ n′ $$=$$ $$0$$. Therefore, the parallelogram is a rhombus. Since the diagonals of a rhombus are at right angles, therefore the required angle is π$$2$$.

The diagonals of the parallelogram whose sides are lx + my + n = 0, lx + my + n′ = 0, mx + ly + n = 0, mx + ly + n′ = 0 include an angle

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