A dice is weighted such that the probability of rolling the face numbered n is proportional to n2 (n = 1, 2, 3, 4, 5, 6). The dice is rolled twice, yielding the numbers a and b. The probability that a < b is p then the value of [2/p] (where [ . ] represents greatest integer function) is _______.
So, total probability = 91 K
Therefore, and so on.
Let three events A, B and C be defined as
By symmetry, P(A) = P(C)
Also, P(A) + P(B) + P(C) = 1
Since
Now, 2P(A) + P(B) = 1