A die is loaded in such a way that each odd number is twice a likely to occur as each even number. If E is the event of a number greater than or equal to 4 on a single toss of the die, then P(E) is:

If a probability p is assigned to each even number, then 2p is the probability to be assigned to each odd number which gives 2p×3+p×3=9p=1⇒p=19 ∴P(E) = probability of getting 4, 5, or 6 =19+29+19=49