A die is thrown a fixed number of times. If probability of getting even number 3 times is same as the probability of getting even number 4 times, then probability of getting even number exactly once is
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a
1/6
b
1/9
c
5/36
d
7/128
answer is D.
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Detailed Solution
According to the given condition, nC312n=nC412n,where n is the number of times die is thrown.∴ nC3=nC4⇒n=7Thus, the required probability is=7C1127=727=7128