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The difference between the greatest and least values of the function $F (x) = \int_{0}^{x} (t + 1) d t on [1, 3]$ is

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Correct option is C

F′(x)=x+1>0 for x∈[1,3] Therefore, the greatest value is F(3) and the least value is F(1). The required difference is ∫03 (t+1)dt−∫01 (t+1)dt=∫13 (t+1)dt=6.

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The difference between the greatest and least values of the function F(x)=∫0x (t+1)dt on [1,3] is

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The difference between the greatest and least values of the function $F (x) = \int_{0}^{x} (t + 1) d t on [1, 3]$ is