Difference between maximum and minimum values of (60sin⁡ α+pcos⁡ α) is 122 then p can be

E=60sin⁡ α+pcos⁡ αMaximum value of E=3600+p2Minimum value of E=−3600+p23600+p2+3600+p2=122∴ 23600+p2=122⇒ p2=121⇒ p=±11