The differential equation for the family of curves x2−y2−2ay=0 where a is an arbitrary constant, is
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a
x2+y2dydx=2xy
b
2x2+y2dydx=xy
c
x2−y2dydx=2xy
d
2x2−y2dydx=xy
answer is C.
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Detailed Solution
We have,x2+y2−2ay=0Differentiating w.r. to x, we get2x+2ydydx−2adydx=0⇒a=x+ydydxdydxSubstituting this value of a in (i), we getx2+y2dydx−2yx+ydydx=0⇒x2−y2dydx=2xyThis is the required differential equation.