Q.

The differential equation satisfied by the system of parabolas y2=4a(x+a) is

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a

ydydx+2xdydx−y=0

b

ydydx2+2xdydx−y=0

c

ydydx2−2xdydx−y=0

d

ydydx2−2xdydx+y=0

answer is B.

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Detailed Solution

The given equation isy2=4ax+adifferentiate both sides we get ⇒2yy1=4a substitute the value of 4a in the given equation y2=2yy1x+yy12y=2y1x+yy12y=2xy1+yy12yy12+2xy1−y=0ydydx2+2xdydx−y=0
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