The differential equation satisfied by the system of parabolas y2=4a(x+a) is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
ydydx+2xdydx−y=0
b
ydydx2+2xdydx−y=0
c
ydydx2−2xdydx−y=0
d
ydydx2−2xdydx+y=0
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
The given equation isy2=4ax+adifferentiate both sides we get ⇒2yy1=4a substitute the value of 4a in the given equation y2=2yy1x+yy12y=2y1x+yy12y=2xy1+yy12yy12+2xy1−y=0ydydx2+2xdydx−y=0