Q.

The digit at the unit place in the number  192005+112005−92005 is

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a

2

b

1

c

0

d

8

answer is B.

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Detailed Solution

(19)2005+(11)2005−(9)2005  =(10+9)2005+(10+1)2005−(9)2005=92005+2005C1(9)2004×10+…+ 2005C0+2005C110+…−(9)2005= 2005C192004×10+ multipleof 10+(1+ multipleof 10)∴ Unit digit =1
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The digit at the unit place in the number  192005+112005−92005 is