The digit at the unit place in the numbers192005 + 112005 _ 92005 is
2
1
0
8
(19)2005+(11)2005−(9)2000=(10+9)2005+(10+1)2005−(9)2005
=92005+2005C1(9)2004×10+…+ 2005C0+2005C110+…−(9)2005 = 2005C192004×10+ multiple of 10+ (1+multipleof10)
∴ Unit digit =1