The distance between the line r→=2i^−2j^+3k^+λ(i−j+4k) and the plane r→.(i^+5j^+k^)=5 is

Distance between the line r→=2i^−2j^+3k^+λ(i−j+4k) and the planer→.(i^+5j^+k^)=5 . Therefore distance of line from this plane=perpendicular distance of point (2,–2, 3)from the plane  i.e. |2−10+3−51+52+1|=1033